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x^2-39x+338=0
a = 1; b = -39; c = +338;
Δ = b2-4ac
Δ = -392-4·1·338
Δ = 169
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{169}=13$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-39)-13}{2*1}=\frac{26}{2} =13 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-39)+13}{2*1}=\frac{52}{2} =26 $
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